What have they done again?
Watch the video to find out
F_0 = \dfrac{1}{4\pi\epsilon_0}\dfrac{|Q_1||Q_2|}{r^2}
Is that equation for defeating Nintendo?
Attraction of charges or bodies? I wonder.
I wonder if Twilight will show up on Christmasโฆ
I finally remembered to turn on the Santa hats (thanks to people pinging me about it being my anniversary).
Guess the thrivesmas period has begun.
Does it though? If you divide a positive number by a smaller and smaller positive number the limit is obviously infinity, but thereโs other kinds of numbers. Dividing the same number by a smaller and smaller negative number gives a totally different limit, negative infinity. This means we donโt know the sign of our answer. The limit of dividing by zero is +/-infinity, which is two answers, which isnโt really a limit, itโs supposed to converge, not diverge. except thereโs a third answer. 0. If you divide zero by smaller and smaller numbers, either positive or negative, you approach 0. So, we approach infinity, negative infinity, and zero, all at once. I wouldnโt call that a limit. Itโs undefined for a reason.
The keyword is โlimit equationโ which has different infinity rules than normal equations. I canโt remember that much math after years of not using most of it, but I think limit equations can very easily and often converge on an infinity even if the limit it approaches is (causing) a division by zero.
Iโd think dividing 0 by 0 would result in 1, since thatโs what other numbers do when divided by themselves.
0/0 is not one. What is one divided by negative one (x/-x for any real x)? itโs negative one. Again, sign matters, and zero does not have an ordinary sign. If zero is of equal sign with itself, youโd be right, but with itโs lack of a sign, 0/0 is in a superposition of +/- 1. or is it? Because if you divide 0 by smaller and smaller numbers, negative or positive, you always get 0. Just like any number divided by zero, weโre stuck with three answers, itโs just replaces infinity with one. If you have three answers, you donโt have an answer, which is what we are looking for. Again, undefined for a reason.
Youโre totally right, but I donโt think that applies to the general case of x/0. think of these two graphs.
Both have a division by zero but the limit exists only for one of them because x^2 is always positive while x can be of either sign. 1/0^2 isnโt any saner of a statement than 1/0, but 1/0 has two directions you can approach it from that have wildly different logical limits, while 1/0^2 kinda just has the one logical limit.
New poll time
- 1 hour ago
- 6 hours ago
- 1 day ago
- 1 week ago
- 2 weeks ago
- 1 month ago
- Even earlier
Oh hey we got little hats again.
You belong to West facing hats, one of us, me, hh. Welcome.
Unless itโs different each client
Itโs different based on the visible post index so itโs going to change for you a lot as well.
Canโt wait until forward-facing hats
Take any 2 ![]()
โthis message too shortโ