What have they done again?
Watch the video to find out
F_0 = \dfrac{1}{4\pi\epsilon_0}\dfrac{|Q_1||Q_2|}{r^2}
Is that equation for defeating Nintendo?
Attraction of charges or bodies? I wonder.
I wonder if Twilight will show up on ChristmasâŚ
I finally remembered to turn on the Santa hats (thanks to people pinging me about it being my anniversary).
Guess the thrivesmas period has begun.
Does it though? If you divide a positive number by a smaller and smaller positive number the limit is obviously infinity, but thereâs other kinds of numbers. Dividing the same number by a smaller and smaller negative number gives a totally different limit, negative infinity. This means we donât know the sign of our answer. The limit of dividing by zero is +/-infinity, which is two answers, which isnât really a limit, itâs supposed to converge, not diverge. except thereâs a third answer. 0. If you divide zero by smaller and smaller numbers, either positive or negative, you approach 0. So, we approach infinity, negative infinity, and zero, all at once. I wouldnât call that a limit. Itâs undefined for a reason.
The keyword is âlimit equationâ which has different infinity rules than normal equations. I canât remember that much math after years of not using most of it, but I think limit equations can very easily and often converge on an infinity even if the limit it approaches is (causing) a division by zero.
Iâd think dividing 0 by 0 would result in 1, since thatâs what other numbers do when divided by themselves.
0/0 is not one. What is one divided by negative one (x/-x for any real x)? itâs negative one. Again, sign matters, and zero does not have an ordinary sign. If zero is of equal sign with itself, youâd be right, but with itâs lack of a sign, 0/0 is in a superposition of +/- 1. or is it? Because if you divide 0 by smaller and smaller numbers, negative or positive, you always get 0. Just like any number divided by zero, weâre stuck with three answers, itâs just replaces infinity with one. If you have three answers, you donât have an answer, which is what we are looking for. Again, undefined for a reason.
Youâre totally right, but I donât think that applies to the general case of x/0. think of these two graphs.
Both have a division by zero but the limit exists only for one of them because x^2 is always positive while x can be of either sign. 1/0^2 isnât any saner of a statement than 1/0, but 1/0 has two directions you can approach it from that have wildly different logical limits, while 1/0^2 kinda just has the one logical limit.
New poll time
- 1 hour ago
- 6 hours ago
- 1 day ago
- 1 week ago
- 2 weeks ago
- 1 month ago
- Even earlier
Oh hey we got little hats again.
You belong to West facing hats, one of us, me, hh. Welcome.
Unless itâs different each client
Itâs different based on the visible post index so itâs going to change for you a lot as well.
Canât wait until forward-facing hats
Take any 2
âthis message too shortâ